Question

How often does a mass on a spring bob up and down if a 10kg mass is attached to a spring with a spring constant of 5 kN/m? In other words, what is the period of oscillation?

Answer 1

The period of oscillation for a mass-spring system with a 10kg mass and a spring constant of 5 kN/m is approximately 0.089 s.

Step-by-step explanation:

The period of oscillation of a mass-spring system can be determined using the equation:

T = 2π√(m/k)

where T is the period, m is the mass of the object, and k is the spring constant. In this case, the mass is 10 kg and the spring constant is 5 kN/m. First, we need to convert the spring constant from kN/m to N/m by multiplying it by 1000:

k = 5 kN/m × 1000 = 5000 N/m

Substituting the values into the equation, we get:

T = 2π√(10/5000)

Calculating this, we find that the period of oscillation is approximately 0.089 s.