Question

An air traffic controller is tracking two planes. To start, Plane A was at an altitude of 468 meters, and plane B was just taking off. Plane A is gaining altitude at 17 meters per second, and Pane B is gaining altitude at 26 meters per second ​how many seconds would it take for the two planes to be at the same altitude​

Answer 1

It will take 52 seconds for Plane A, ascending at 17 meters per second from an initial altitude of 468 meters, and Plane B, ascending at 26 meters per second from the ground, to reach the same altitude.

Step-by-step explanation:

To calculate how many seconds it will take for Plane A, which starts at an altitude of 468 meters and ascends at 17 meters per second, to match the altitude of Plane B, which is ascending from the ground at 26 meters per second, we set up an equation that equals the altitudes of both planes over time. Let's assume t is the time in seconds after both planes have started climbing. We can express the altitude of Plane A as 468 + 17t and the altitude of Plane B as 26t. To find the time when the altitudes are equal, we set the expressions for altitudes equal to each other and solve for t:

468 + 17t = 26t

Moving like terms to one side, we get:

468 = 26t - 17t

468 = 9t

Now divide both sides by 9:

t = 468 / 9

t = 52 seconds

Therefore, it will take 52 seconds for Plane A and Plane B to reach the same altitude.