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If a sample of gas has a volume of 4.71L at 66.1˚C, what volume will it occupy at 41.1˚C?

User Lawitschka
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Answer:4.71 L / (66.1 + 273.15) K = V₂ / (41.1 + 273.15) K

Solving for V₂, we get:

V₂ = 4.71 L * (41.1 + 273.15) K / (66.1 + 273.15) K = 3.87 L 1.

Therefore, the volume of the gas at 41.1˚C will be 3.87 L.

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