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Consider the equation of the line that passes through point (-4,1)and (2,19)

User Caktux
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Final answer:

The equation of the line is y = 3x + 13 which passes through the points (-4,1) and (2,19)

Step-by-step explanation:

The equation of the line that passes through the points (-4,1) and (2,19) can be found using the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

First, find the slope (m) using the formula: m = (y2 - y1)/(x2 - x1). Substitute the coordinates of the two points into the formula to get: m = (19 - 1)/(2 - (-4)) = 3.

Next, substitute one of the points and the slope into the equation to find the y-intercept (b). Using the point (-4,1), we have: 1 = 3(-4) + b. Solving for b, we get: b = 13.

Therefore, the equation of the line is y = 3x + 13.

User Jarmod
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