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a population of bacteria doubles every day.on day 6 there were 448 bacteria. how many bacteria will there be on dayv10

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There will be 7,168 bacteria on day 10.

The population of bacteria doubles every day, which indicates exponential growth. If on day 6 there were 448 bacteria, then each day the population doubles. To find the number of bacteria on day 10, we can use the formula for exponential growth:

Population=Initial Population×(2^Number of Days)

Given that on day 6 there were 448 bacteria, we can substitute these values into the formula:

Population on day 10=448×(2^10−6)

Solving this, we get:

Population on day 10=448×2^4=448×16=7,168

Therefore, there will be 7,168 bacteria on day 10.

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