Question

a bee flies with a velocity of 0.25 m/s to the left, and 0.46 m/s down. Find the magnitude of its velocity, express your answer in m/s

Answer 1

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  `\large\boxed{\sf v = 0.52 \ m/s }`

Step-by-step explanation:

We are here given that the bee flies with velocity of 0.25m/s towards left and 0.46m/s down.

This means that the bee is moving towards -î and towards -j respectively.

So the net velocity can be expressed as ;

`\displaystyle\implies \vec{v} = (0.25\ \hat{-i} + 0.46 \ \hat{-j} ) \ m/s \\\\`

`\implies \vec{v} = (-0.25\hat{i} - 0.46\hat{j} ) \ m/s \\\\`

Now we are interested in finding the magnitude of the velocity. velocity is a vector and say if we have any vector

`\implies \vec{A} = a\hat{i} + b\hat{j} \\\\`

Then its magnitude is given as;

`\implies A = √( a^2+b^2)\\`

Hence here the magnitude will be;

`\implies v = √((0.25)^2+(0.46)^2) \ m/s \\\\`

`\implies v = √(0.2741) \ m/s \\\\`

`\implies \boxed{ v = 0.52 \ m/s} \\\\`

Hence the magnitude of the velocity is 0.52 m/s.