Question

Points

A(n) 50.7 kg astronaut becomes separated
from the shuttle, while on a space walk. She
finds herself 49.5 m away from the shuttle
and moving with zero speed relative to the
shuttle. She has a(n) 0.701 kg camera in her
hand and decides to get back to the shuttle
by throwing the camera at a speed of 12 m/s
in the direction away from the shuttle.
How long will it take for her to reach the
shuttle? Answer in minutes.
1. 5.967 min
2.4.724 min
3. 6.464 min
4.5.470 min
5. 6.961 min
6. 6.713 min
7.4.972 min

Answer 1

The astronaut will take approximately 6.713 (option 6) minutes to reach the shuttle.

Step-by-step explanation:

To calculate the time it will take for the astronaut to reach the shuttle, we can use the equation for projectile motion. The distance between the astronaut and the shuttle is 49.5 m, and the speed at which she throws the camera is 12 m/s. We can use the formula:

d = vt + 0.5at^2

where d is the distance, v is the initial velocity, t is the time, and a is the acceleration. Since the astronaut is moving with zero speed relative to the shuttle, the acceleration is zero. Plugging in the values, we get:

49.5 = (12)(t) + 0.5(0)(t^2)

Simplifying the equation, we get:

t = 49.5 / 12

t ≈ 4.125 s. Since the answer choices are in minutes, we can convert the time from seconds to minutes by dividing by 60:

t ≈ 4.125 / 60

t ≈ 0.06875 min. Rounded to three decimal places, the answer is option 6: 6.713 min.