Question

According to the following balanced chemical equation, how many moles of chlorine are need to produce 19.0 grams of FeCl3?

Answer 1

Answer: 0.175 moles of chlorine are need to produce 19.0 grams of
`FeCl_3`

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}*{\text{Molar Mass}}`

`\text{Moles of} FeCl_3=(19.0g)/(162.2g/mol)=0.117moles`

The balanced chemical equation is:

`2Fe+3Cl_2\rightarrow 2FeCl_3`

According to stoichiometry :

2 moles of
`FeCl_3` require = 3 moles of
`Cl_2`

Thus 0.117 moles of
`FeCl_3` will require=
`(3)/(2)* 0.117=0.175moles` of
`Cl_2`

Thus 0.175 moles of chlorine are need to produce 19.0 grams of
`FeCl_3`