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Z multiplied by 161 is the same as z

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The value of (z) is 0, as the product of (z) and 161 is equal to z only when (z) is 0. This is due to the property that any number multiplied by 0 results in 0, satisfying the given condition in the equation z*161 = z.

In mathematical terms, the statement "the product of a number z and 161 is equal to the number itself" can be expressed as the equation "z * 161 = z." To find the value of z, we can rearrange the equation and solve for z:

z * 161 - z = 0

z(161 - 1) = 0

This equation implies that either z = 0 or 161 - 1 = 160. However, since the question is asking for the value of z when the product is equal to the number itself, the solution is z = 0. This is because any number multiplied by 0 is 0.

Therefore, the value of z that satisfies the given condition is z = 0.

Complete question should be:

If the product of a number z and 161 is equal to the number itself, what is the value of z?

User Cnelson
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