The molecule C10H14N2 has 5 rings, determined through unsaturation analysis based on its molecular formula. The formula calculates unsaturation, and the number of rings is derived as unsaturation - 1.
Number of rings in C10H14N2
The molecule C10H14N2 has 5 rings. This can be determined by analyzing its molecular formula and applying the concept of unsaturation.
Unsaturation refers to the presence of double bonds or rings in a molecule. We can calculate the number of rings and double bonds using the following formula:
Unsaturation = (Valence electrons - 2 * Total atoms) / 2
For C10H14N2:
Valence electrons: (10 x 4) + (14 x 1) + (2 x 5) = 58
Total atoms: 10 + 14 + 2 = 26
Therefore, unsaturation = (58 - 2 x 26) / 2 = 6
Since rings contribute one less double bond to unsaturation, the number of rings is unsaturated - 1 = 6 - 1 = 5.
In summary, the molecule C10H14N2 has 5 rings.
The question probable may be:
What is the method for determining the number of rings in a molecule based on its molecular formula and the concept of unsaturation? Use the example of C10H14N2 to illustrate the calculation and explain how unsaturation is related to the presence of rings in a molecule.