Question

7. AHIJ = APQR. Solve for x. Then find the missing

sides. H
3x
H
x+32
R
J
2x
x+64

Answer 1

AHIJ = APQR

equal triangles, sides are equal

x+64=3x

2x = x+32

x+64=3x

x-3x=-64

-2x=-64

x=32°

angles are calculated :

x+64 = 32+64=96°

3x =32*3 = 96°

2x=x+32

2x=2*32 =64°

x+32 = 32+32+64°

Explanation: