Question

Apply limits to solve:

At ice temperatures (below 5 °C), the vapor pressure of water is negligible. The volume at that point is due to the air alone, within the limits of the measurements. Using the gas law equation, the number of moles of air in the cylinder is calculated: (Use R = 62.4 L*torr*K-1mol-1) n=PVcold/RTcold Using the corrected value for volume, the lowest measured temperature and the atmospheric pressure, calculate the number of moles of trapped air. Important: This value is required for all other calculations Pressure of the room= 29.03 in Hg V1= 8.3 mL V2= 9.3 mL

Answer 1

To calculate the number of moles of trapped air, you can use the ideal gas law equation. Given the volume of air and the pressure, calculate the change in volume and use the gas constant to find the number of moles of air.

Step-by-step explanation:

To calculate the number of moles of trapped air, we can use the ideal gas law equation:

n = (P * V) / (R * T)

Given that the volume of air in the cylinder is V1 = 8.3 mL and V2 = 9.3 mL, we can calculate the change in volume as dV = V2 - V1 = 9.3 mL - 8.3 mL = 1 mL. Since the pressure remains constant at atmospheric pressure (P = 29.03 in Hg = 760 mmHg), we can assume the temperature also remains constant.

Using the given value for the gas constant R = 62.4 L*torr*K^-1mol^-1, we can plug in the values into the formula:

n = (P * dV) / (R * T)

n = (760 mmHg * 1 mL) / (62.4 L*torr*K^-1mol^-1 * 273 K)

n = 0.0263 moles of air