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One 2.0 kg object is 4.5 m north of a second object of 3.0 kg. A third object of mass 17.0 kg is 1.0 m due south of the 3.0 kg object. Find the center of mass of this system.

1 Answer

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Final answer:

The center of mass of this system is approximately 0.364 m south of the origin.

Step-by-step explanation:

The center of mass of a system can be found by considering the mass and position of each object in the system.

To find the center of mass in this system, we can use the formula:

center of mass = (m₁x₁ + m₂x₂ + m₃x₃) / (m₁ + m₂ + m₃)

where m is the mass of each object and x is the position of each object. Plugging in the values:

center of mass = (2.0 kg * 4.5 m + 3.0 kg * 0 m + 17.0 kg * -1.0 m) / (2.0 kg + 3.0 kg + 17.0 kg)

center of mass = (9.0 kg*m + 0 kg*m - 17.0 kg*m) / 22.0 kg

center of mass = -8.0 m / 22.0 kg

center of mass ≈ -0.364 m

Therefore, the center of mass of this system is approximately 0.364 m south of the origin.

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