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a flask contains 8.28 L of a 6.41 lithium chloride (LiCl) solution. how many grams of lithium chloride are in the solutions?

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Final answer:

To find the number of grams of LiCl in an 8.28 L solution with a concentration of 6.41 M, multiply the volume by the molarity and the molar mass of LiCl. The calculation gives a result of 2233.17 grams of LiCl.

Step-by-step explanation:

To calculate the number of grams of lithium chloride (LiCl) in the solution, we need to use the molarity of the solution and its volume.

The molarity is given as 6.41 M, which means 6.41 moles of LiCl are present per liter of solution. The volume of the solution is 8.28 L.

Therefore, the total moles of LiCl are 6.41 moles/L × 8.28 L. To find the mass, we need to multiply the total moles by the molar mass of LiCl (42.39 g/mol).

The equation is:

Mass of LiCl = Total moles of LiCl × Molar mass of LiCl

Mass of LiCl = 6.41 moles/L × 8.28 L × 42.39 g/mol

Mass of LiCl = 2233.17 grams.

Thus, there are 2233.17 grams of LiCl in the 8.28 L solution.

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