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Equation of line parallel to given line and passes through a point
y=1/2x+8 (-6,4)

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Final answer:

The equation of the line that is parallel to the given line y = 1/2x + 8 and that passes through the point (-6,4) is y = 1/2x + 7.

Step-by-step explanation:

The student is seeking the equation of a line that is parallel to a given line and passes through a particular point. The given line is y = ½x + 8, and the line that is parallel to it must have the same slope, which is ½ in this case. Since the line must go through the point (-6,4), we can use the point-slope form to find the equation of the desired line:

y - y1 = m(x - x1)

Substituting the point (-6,4) and the slope ½ yields:

y - 4 = ½(x + 6)

Expanding and simplifying, we get:

y = ½x + 3 + 4

y = ½x + 7

Therefore, the equation of the line parallel to the given line and passing through the point (-6,4) is y = ½x + 7.

User Tony Hinkle
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