Final answer:
The maximum mass of calcium chloride that can be produced by reacting 8.02 grams of calcium with excess hydrochloric acid is 22.22 grams.
Step-by-step explanation:
You want to calculate the maximum mass of calcium chloride produced by reacting 8.02 grams of calcium with excess hydrochloric acid. The reaction between calcium and hydrochloric acid is as follows:
Ca + 2HCl → CaCl2 + H2
First, we need to find the number of moles of calcium that is reacting. Using the relative atomic mass of calcium (Ca=40.1), we can calculate:
Number of moles of Ca = mass of Ca / relative atomic mass of Ca
Number of moles of Ca = 8.02 g / 40.1 g/mol
= 0.20 moles (rounded to two decimal places)
Since the reaction requires 1 mole of calcium to produce 1 mole of calcium chloride (CaCl2), the number of moles of calcium chloride that will be produced is the same as the number of moles of calcium that reacted, which is 0.20 moles.
Now, using the relative formula mass of CaCl2 (111.1), we can find the maximum mass of calcium chloride:
Mass of CaCl2 = number of moles of CaCl2 × relative formula mass of CaCl2
Mass of CaCl2 = 0.20 moles × 111.1 g/mol = 22.22 g
Therefore, the maximum mass of calcium chloride that can be produced is 22.22 grams.