Final answer:
The final velocity of the two train cars after the collision is -0.0532 m/s.
Step-by-step explanation:
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
To calculate the final velocity, you can use the equation:
m1 * v1 + m2 * v2 = (m1 + m2) * vf
Plugging in the values:
(150,000 kg * 0.300 m/s) + (110,000 kg * -0.120 m/s) = (150,000 kg + 110,000 kg) * vf
Solving for vf, the final velocity, you will get:
vf = -0.0532 m/s