Question

A body of mass 200g is executing simple harmonic motion with amplitude of 20m. The maximum force which acts upon it is 0.8N. Calculate its maximum velocity and its period of oscillation

Answer 1

w=0.8/0.2 kg x 20m =0.2s^-2
square root for both sides is
w=0.447s^-1


maximum velocity

vmax=0.447s^-1 x 20m
vmax = 8.94 m/s

period T

T=2pie/0.447s^-1
T=14.08 s

so
velocity is 8.94 m/s
and period T is 14.08 s