Question

A system releases 481 kJ of heat while 390 kJ of work is done on the system. What is the change in internal

energy?

Answer 1

ΔE = q + w

here q = -136 kj

w = 146

so ΔE = -136 + 146 = 10 kj

thus internal energy of system increases by 10 kj...

I hope this helps! :) I don't know if it's the right one