Question

If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When will the object hit the ground?

Answer 1

The object hits the ground after 3.52 seconds.

Explanation:

The height of the object after t seconds is given by the following function:

`h(t) = -16t^2 + 198`

When will the object hit the ground?

It hits the ground when
`h(t) = 0`. So

`-16t^2 + 198 = 0`

`16t^2 = 198`

`t^2 = (198)/(16)`

`t^2 = 12.375`

`t = \pm √(12.375)`

Since time is a positive measure, we only take the positive value

`t = 3.52`

The object hits the ground after 3.52 seconds.