Question

Raul is performing an experiment. He pours water into a glass and measures the temperature of the water at 72.3°F. Then he adds a few ice cubes to the glass of water. He measures the temperature of the water again and finds that it has changed by -39.1°F.

Several minutes later, Raul decides to measure the water temperature again. He finds that the temperature changed by -0.6°F. What is the temperature of the water now? Show your work.​

Answer 1

32.6°F.

Explanation:

The initial temperature of the water was 33.2°F. After several minutes, the temperature of the water changed by -0.6°F. So, the new temperature of the water is

33.2 + (-0.6)

=

(30 + 3) + [0.2 + (-0.6)]

=

33 + (-0.4)

=

33 – 0.4

=

32.6°F.

copied the answer from Edmentum

Answer 2

72.3-39.1-0.6= 32.6F