Final Answer:
The stress applied to the soft-tissue specimen prepared from an axial segment of the human aorta is 481.48 kPa.
Step-by-step explanation:
The stress applied to the soft-tissue specimen can be calculated using the formula stress (σ) = force (F) / area (A). Given that the force (F) is 1.3 N and the thickness of the healthy tissue specimen is 2.7 mm, we need to convert the thickness to meters by dividing it by 1000, resulting in 0.0027 m.
The area can be calculated using the formula A = thickness x 1 (assuming a unit width for simplicity). Substituting these values into the stress formula, we get σ = 1.3 N / (0.0027 m x 1), which equals 481.48 kPa.
This calculation indicates that the stress applied to the soft-tissue specimen is 481.48 kPa, which represents the force per unit area experienced by the tissue. Understanding this stress is crucial in assessing how the tissue responds to external forces and can provide valuable insights into its mechanical properties and behavior under different conditions.
In biomedical engineering and medical research, understanding the mechanical properties of soft tissues like those found in the human aorta is essential for developing treatments and interventions for cardiovascular diseases. By quantifying the stress applied to such tissues, researchers can gain a deeper understanding of their behavior and contribute to advancements in medical technology and treatment options.