Question

. using inverse laplace table, find the inverse laplace transform of following functions f1 (s) = 2 s 2 8s 16 ,

Answer 1

To find the inverse Laplace transform of f1(s) = 2s^2 - 8s + 16, you can use the inverse Laplace transform table. The inverse Laplace transform of f1(s) is 2t^2 - 8t + 16.

Step-by-step explanation:

To find the inverse Laplace transform of f1(s) = 2s^2 - 8s + 16, we can use the inverse Laplace transform table.

Let's break down f1(s) into its individual terms:

• L^-1(2s^2) = 2t^2
• L^-1(-8s) = -8t
• L^-1(16) = 16

Now, combine these individual inverse Laplace transforms to find the overall inverse Laplace transform of f1(s):

L^-1(f1(s)) = 2t^2 - 8t + 16