Question

An arrow is fired at 5.20 m s−1 at an angle of 22.0° above the horizontal. Find the horizontal component of the initial velocity, expressing your answer in m s−1 to 2d.P.\

Answer 1

`4.82ms^(-1)`

Step-by-step explanation:

We are given that

Initial velocity, u=5.20m/s

`\theta=22^(\circ)`

We have to find the horizontal component of the initial velocity.

We know that

Horizontal component of velocity=
`ucos\theta`

Using the formula

Horizontal component of the initial velocity=
`5.2cos22^(\circ)`

Horizontal component of the initial velocity=
`5.2* 0.9272`

Horizontal component of the initial velocity=
`4.82ms^(-1)`

Hence, the horizontal component of the initial velocity=
`4.82ms^(-1)`