Final answer:
The function f(x) = ln(x-26) is discontinuous at x = 26 because the natural logarithm function is not defined for negative or zero inputs.
Step-by-step explanation:
The function f(x) = ln(x-26) is discontinuous at x = 26 because the natural logarithm function is not defined for negative or zero inputs. Since x = 26 results in the argument of the logarithm becoming zero, the function is undefined at x = 26 and therefore discontinuous at that point.
The graph of the function will have a vertical asymptote at x = 26 due to the discontinuity.