Final answer:
To calculate the new value for the x-component of the electric field Ex(p) at point p when an infinite line is moved parallel to the y-axis at x = -4.75cm, use Coulomb's Law with the concept of linear charge density. Considering that the electric field is always perpendicular to the line of charge and radially outward, apply the equation Ex = (1/(4πε_0)) * (2λ/r), substituting the appropriate values for linear charge density and the distance from the charge.
Step-by-step explanation:
The student's question about calculating the electric field Ex(p), when an infinite line of charge is parallel to the y-axis at x = -4.75cm, pertains to the topic of electric fields in classical electromagnetism. Since the line of charge is infinite and parallel to the y-axis, the electric field at any point will be perpendicular to the line of charge and directed radially outward (or inward if the charge is negative). The new value of Ex(p) at point p, particularly its x-component, can be calculated using Coulomb's Law and the concept of linear charge density.
For a uniformly charged infinite line, the x-component of the electric field Ex at a distance r (which in this case would be 4.75 cm or 0.0475 meters) can be determined using the equation:
Ex = (1/(4πε_0)) * (2λ/r)
where λ represents the linear charge density and ε_0 is the permittivity of free space. The student would need to substitute the specific charge density value for λ to find Ex(p).
Furthermore, as per Equation 19.45, the voltage V across parallel plates is directly proportional to the electric field strength E and the distance d, i.e., V = Ed, which relates to the concept of voltage in a uniform electric field.