Final answer:
To find the required volume of 0.100 M sodium carbonate to produce 1.00 g of calcium carbonate, one should write the balanced equation, calculate moles of calcium carbonate from the given mass, find the moles of sodium carbonate needed, and finally calculate the volume using the molarity.
Step-by-step explanation:
To determine the volume (in mL) of 0.100 M sodium carbonate required to produce 1.00 g of calcium carbonate with an excess of calcium chloride, the following steps should be ordered:
- Write the balanced chemical equation for the reaction between sodium carbonate and calcium chloride to form calcium carbonate.
- Calculate the number of moles of calcium carbonate that correspond to 1.00 g.
- Use the stoichiometry of the balanced equation to determine the number of moles of sodium carbonate needed to react with calcium carbonate.
- Convert the moles of sodium carbonate to volume using the molarity of the sodium carbonate solution.
For example, to calculate the mass of calcium chloride needed to produce 10 g of calcium carbonate, you would use the molar masses of the reactants and products and the stoichiometry of the reaction. Similarly, when preparing solutions, like a 1.00 M solution of NaCl, it’s important to consider the volume change upon dissolution. This is also crucial when discussing concentrations regarding titrations and equilibrium concentrations in reactions.