Question

Calculate the molarity of the following solutions:

a) 0.300 mol of Na2S in 1.25 L of solution.
b) 30.9 g of MgS in 959 mL of solution.

Answer 1

Answer:
a) 0.24M
b) O.575M
Step-by-step explanation:
Molarity = no of moles/volume
= .300/1.25
=0.24 M

b) Molar mass of MgS = 56g/molmo
no of mole = mass/m.mass
= 30.9/56
=0.55 moles


TO CONVERT VOLUME FROM ML TO L

959/1000 Litres= 0.959L

Molarity = .55/.959
=0.575M

Answer 2

To calculate the molarity of a solution, use the formula: molarity = moles of solute / volume of solution (in L). In the given examples, the molarity of the Na2S solution is 0.240 M, and the molarity of the MgS solution is 0.539 M.

Step-by-step explanation:

To calculate the molarity of a solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in L)

a) For the first solution, we have 0.300 mol of Na2S in 1.25 L of solution. Therefore, the molarity is 0.300 mol/1.25 L = 0.240 M.

b) For the second solution, we have to convert the mass of MgS to moles using the molar mass and then divide by the volume in liters. The molar mass of MgS is 56.3 g/mol. So, we have (30.9 g / 56.3 g/mol) / (959 mL / 1000 mL/L) = 0.539 M.