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A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the equation x(t)= (alpha * t^2) - (beta * t³), where alpha = 1.55m/s² and beta = 4.70 * 10⁻² m/s³

A. Calculate the average velocity of the car for the time interval t=0 to t1 = 2.00s .
B. Calculate the average velocity of the car for the time interval t=0 to t2 = 3.96s
C. Calculate the average velocity of the car for the time interval t1 = 2.00s to t2 = 3.96s .

1 Answer

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Final answer:

To find the average velocity of a Honda Civic over various time intervals, use the given position function, calculate displacements at the specific times, and divide by the respective time intervals.

Step-by-step explanation:

To calculate the average velocity of the Honda Civic for different time intervals, we use the position function x(t) = (alpha * t^2) - (beta * t^3) provided in the question, where alpha = 1.55 m/s² and beta = 4.70 x 10⁻² m/s³.

A. For the time interval from t=0 to t1=2.00 s, the average velocity is calculated as:

  • First, we compute the car's displacement by plugging t1 into the position function: x(t1) = (1.55 m/s²)(2.00 s)² - (4.70 x 10⁻² m/s³)(2.00 s)³.
  • Next, we divide the displacement by the time interval (t1 - 0) to find the average velocity.

B. Similarly, for the interval t=0 to t2=3.96 s, we calculate the displacement at t2 and divide by t2 to find the average velocity.

C. To find the average velocity for the interval from t1=2.00s to t2=3.96s, we calculate:

  • The displacement at t2 as before.
  • The displacement at t1 as before.
  • Subtract the displacement at t1 from that at t2 to get the car's change in position for this interval.
  • Divide this change in position by the time difference (t2 - t1) to determine the average velocity.
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