Final answer:
The Unsaturation Number (UN)/Double-Bond Equivalent (DBE) for Compound A with the molecular formula C6H14O is 0, indicating there are no double bonds, rings, or triple bonds, and therefore cannot be a double bond in Compound A.
Step-by-step explanation:
Calculating the Unsaturation Number (UN) / Double-Bond Equivalent (DBE)
The Unsaturation Number (UN), also known as the Double-Bond Equivalent (DBE), helps us determine the level of unsaturation in a compound. This concept informs us about the number of double bonds, rings, or triple bonds that a compound may contain. To calculate the UN/DBE for a compound, you can use the formula for alkanes, which is CnH(2n+2). Comparing the actual hydrogen count to the hydrogen count of an equivalent alkane can provide us with the UN/DBE.
For Compound A (C6H14O), the equivalent alkane would have the formula C6H14 (since oxygen does not change the hydrogen count). Here, the total number of hydrogens is as expected for a saturated hydrocarbon with the same number of carbons (2n + 2 = 2(6) + 2 = 14 H's). Therefore, the UN/DBE is 0, indicating no degree of unsaturation, no double bonds, no rings, and no triple bonds in the structure.
Given the UN/DBE of 0, it can be concluded that there cannot be a double bond in Compound A. It is a fully saturated compound.