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how many years will it take for an initial investment of 20000 to grow to 30000? assume a rate of interest of 16% compound continuously

User Es
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Final answer:

It will take approximately 12.59 years for an initial investment of $20,000 to grow to $30,000, assuming a continuous compound interest rate of 16%.

Step-by-step explanation:

To calculate how many years it will take for an initial investment of $20,000 to grow to $30,000 with a continuous compound interest rate of 16%, we use the formula for continuous compounding, which is A = Pert, where:

A is the amount of money accumulated after n years, including interest.

P is the principal amount (the initial amount of money).

r is the annual interest rate (decimal).

t is the time in years.

e is the base of the natural logarithm, approximately equal to 2.71828.

We know A = $30,000, P = $20,000, r = 0.16, and e is a constant. We need to solve for t:

30000 = 20000 * e(0.16t)

Divide both sides by 20000:

1.5 = e(0.16t)

Take the natural logarithm of both sides:

ln(1.5) = ln(e(0.16t))

Using the property of logarithms, we simplify:

ln(1.5) = 0.16t * ln(e)

Since ln(e) = 1:

ln(1.5) = 0.16t

Now, solve for t:

t = ln(1.5) / 0.16 ≈ 2.014 / 0.16 ≈ 12.59 years

Therefore, it will take approximately 12.59 years for the investment to grow from $20,000 to $30,000 at a 16% continuous compound interest rate.

User ScruffyDuck
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