Question

81.0 mol of P4O10 contains how many moles of P?

Answer 1

81.0 moles of P4O10 contains 324 moles of phosphorus (P), as each molecule of P4O10 has 4 atoms of P.

Step-by-step explanation:

If you have 81.0 moles of P4O10, to find out how many moles of phosphorus (P) are in the compound, we should consider the stoichiometry of the molecule. P4O10 contains 4 atoms of phosphorus for each molecule. Therefore, the number of moles of P is 4 times the number of moles of P4O10.

So, the calculation would be:

81.0 moles P4O10 x 4 moles P per mole of P4O10 = 324 moles of P.