Question

A bookstore sells hardback books for $8 each and paperback books for $5 each. If the bookstore sells a total of 88 books and makes $599, exactly how many hardback books does the bookstore sell?.

Answer 1

By setting up and solving a system of equations, it is calculated that the bookstore sells 53 hardback books.

Step-by-step explanation:

To determine the number of hardback books sold by the bookstore, we can set up a system of equations based on the information provided: the price of hardback books, the price of paperback books, the total number of books sold, and the total earnings.

Let H be the number of hardback books sold and P be the number of paperback books sold. We have two equations:

1. H + P = 88 (the total number of books sold)
2. $8H + $5P = $599 (the total earnings from book sales)

Now, solve this system of equations. We can start by multiplying the first equation by 5, which gives us 5H + 5P = 440. Subtract this from the second equation to eliminate the P variable:

$8H + $5P = $599

-(5H + 5P = 440)

This gives us $3H = $159, and when we divide both sides by 3, we find H = 53.

Therefore, the bookstore sells 53 hardback books.

Answer 2

53 hardback books the store sold

Step-by-step explanation:

Let

the number of hardback books for $8 each be x

the number of paperback books for $5 each be y

Write the system of equation for number of books and amount of money made from selling them.

Sells a total of 88 books and makes $599

x+y = 88

8x+5y = 599

How many hardback books (x) does the bookstore sell?

Find x by solving the system of equations:

x+y = 88 , multiply by -5 to eliminate y

8x+5y = 599

-5x-5y = -440

8x+5y = 599

---------------------, add the two equations

3x = 159, divide on both side of equal sign by 3

x = 53