Question

A jack system will increase the potential energy of a heavy load by 1000 J with a work input of 2000 J. The efficiency of the jack system is?

1) 50%
2) 60%
3) 70%
4) 80%

Answer 1

The efficiency of the jack system, which increased the potential energy of a heavy load by 1000 J with a work input of 2000 J, is calculated as 50%. This is based on the formula where Efficiency (%) = (Useful Energy Output / Total Energy Input) x 100.

Step-by-step explanation:

The efficiency of a jack system can be calculated using the formula: Efficiency (%) = (Useful Energy Output / Total Energy Input) x 100. In this case, the useful energy output is the increase in potential energy of the heavy load, which is 1000 J, and the total energy input is the work done to lift this load, which is 2000 J.

Now let's calculate the efficiency:

Efficiency = (1000 J / 2000 J) x 100 = 0.5 x 100

Efficiency = 50%

Therefore, the efficiency of the jack system is 50%, which corresponds to option 1.