Final answer:
The heat required to melt 50 grams of 0-degree-Celsius ice is 16,700 joules, using the heat of fusion for water which is 334 joules per gram.
Step-by-step explanation:
To calculate the amount of heat required to melt 50 grams of 0-degree-Celsius ice, we need to know the heat of fusion for water. The heat of fusion is the amount of energy needed to change 1 gram of a substance from the solid phase to the liquid phase at its melting point without changing its temperature. For water, the heat of fusion is approximately 334 joules per gram (J/g). Therefore, the heat (Q) required to melt the ice can be calculated using the formula:
Q = m * Lf
Where:
- m is the mass of the ice (in grams)
- Lf is the heat of fusion of ice (in J/g)
For 50 grams of ice, the calculation would be:
Q = 50 g * 334 J/g
Q = 16700 J
So, 16700 joules of heat are required to melt 50 grams of 0-degree-Celsius ice.