Final answer:
To find the charge density on parallel conducting plates, use the formula σ = Q/A. The electric field between the plates with opposite charges can be found with E = σ/ε₀, where ε₀ is the vacuum permittivity.
Step-by-step explanation:
The student's question is related to the electrical properties of two large, parallel conducting plates with opposite charges. To find the charge density on the inside surface of each plate, you can use the formula σ = Q/A, where σ is the surface charge density, Q is the charge on the plate, and A is the area of the plate. For two 10 cm x 10 cm plates with charges of ±8.0 µC, the area A is (0.1 m)(0.1 m) = 0.01 m², so the charge density σ would be (8.0 × 10⁻¶ C)/(0.01 m²) = 0.8 µC/m².
To determine the electric field between the plates, you would use the expression E = σ/ε₀, where E is the electric field, σ is the surface charge density, and ε₀ is the vacuum permittivity. For a surface charge density of 0.8 µC/m², this would result in an electric field E = (0.8 µC/m²) / (8.85 × 10⁻¹² C²/N⋅m²) = 9.04 × 10³ N/C between the plates, directed from the positively charged plate to the negatively charged plate.