Question

Consider two populations, with p = 0.3 and q = 0.7 in pop1 and p= 0.4 and q = 0.6 in pop2. Suppose individuals migrate from pop2 to pop1 such that the immigrants comprise 5

1) p = 0.35, q = 0.65
2) p = 0.4, q = 0.6
3) p = 0.45, q = 0.55
4) p = 0.5, q = 0.5

Answer 1

The frequency of the AA genotype when p = 0.4 is 0.16 or 16%, as per the Hardy-Weinberg equilibrium equation, which is represented by p².

Step-by-step explanation:

The student's question relates to population genetics and the Hardy-Weinberg principle, which describes the genetic equilibrium within a population under certain conditions. Assuming p represents the frequency of the dominant allele A and q represents the frequency of the recessive allele a, and given that p = 0.4 in the question, the frequency of the AA genotype, according to the Hardy-Weinberg equilibrium equation, is p². Therefore, for p = 0.4, the frequency of the AA genotype is 0.4² = 0.16 or 16%.