Question

Imagine two people, each with a 650 Newton weight. Also suppose one person carries a + 1 Coulomb charge, while the other carries a - 1 Coulomb charge. A. How far apart would they be, so that their force of attraction also equals 650 N? (3.7 km) B. Suppose they were only 10 meters apart. If the only unbalanced force acting on them was electrical, calculate their initial accelerations.

Answer 1

To find the distance at which the force of attraction between two charged objects equals 650 N, we can use Coulomb's law. The distance is approximately 3.7 km. If the two charged objects are only 10 meters apart, their initial accelerations can be calculated using Coulomb's law.

Step-by-step explanation:

To find the distance at which the force of attraction between two charged objects equals 650 N, we can use Coulomb's law:

Force = k * (charge1 * charge2) / (distance^2)

Since the force is 650 N and both charges are 1 Coulomb, we can rearrange the equation to find the distance:

distance = sqrt((k * (charge1 * charge2)) / force)

Plugging in the values, we get: distance = sqrt((9 x 10^9 N m^2/C^2 * (1 C * 1 C)) / 650 N) = 3700 meters (or 3.7 km)

If the two charged objects are only 10 meters apart, we can calculate their initial accelerations using Coulomb's law:

Acceleration = (k * (charge1 * charge2)) / (mass * distance^2)

Since the masses are not given, we can assume they are equal. Plugging in the values, we get: acceleration = (9 x 10^9 N m^2/C^2 * (1 C * 1 C)) / (650 N * (10 m)^2) = 140 m/s^2