Final answer:
In this circuit with parallel connected bulbs, one burned out bulb will not affect the others, and the normal operating voltage of each bulb can be calculated by dividing the total voltage by the number of bulbs.
Step-by-step explanation:
In the circuit shown, all bulbs are connected in parallel to the battery. This means that each bulb has the same potential difference across it.
- When one bulb in the circuit burns out, the other bulbs will continue to light up because the circuit remains complete. The burned out bulb acts like an open switch, but the flow of current can still pass through the other bulbs.
- The normal operating voltage of each bulb in the circuit is 120 V divided by the number of bulbs. In the case of 40 identical bulbs, the normal operating voltage of each bulb is 120 V / 40 = 3 V.
- In the case of the newer version of holiday lights, if one bulb burns out, it acts like a closed switch. This means that the circuit becomes short-circuited and no current flows through the remaining bulbs, so they will not light up.
- If there are 39 remaining identical bulbs in the circuit, the operating voltage of each bulb can be calculated by dividing the total voltage of the circuit by the number of bulbs. In this case, the operating voltage of each remaining bulb is 120 V / 39 ≈ 3.08 V.