Final answer:
The vector momentum of block 2 at 5 seconds after noon cannot be determined without additional information about the forces acting on it after it was at rest. For an accurate calculation, details regarding the velocity or the specific context are required.
Step-by-step explanation:
To determine the vector momentum of block 2 at 5 seconds after noon, more information regarding the context of the interaction or specifics about the forces acting on block 2 after they were at rest at 4.2 seconds would be necessary. Momentum is a vector quantity defined as the product of an object's mass and its velocity. Since the blocks were initially at rest, any momentum at 5 seconds would depend on the forces that have acted on the block during that interval. The information provided does not specify any forces acting on block 2 or its resultant velocity. Without that information, we cannot accurately calculate the vector momentum. The question may be referring to a specific scenario or textbook example, so please provide more details or context for further assistance.
However, if this was an isolated system with no external forces acting on it and block 2 remained at rest, then its momentum at 5 seconds after noon would still be zero, since momentum equals mass times velocity (p = m*v), and the velocity of block 2 would remain 0 m/s if it is still at rest.