Question

According to the following reaction, how many moles of calcium carbonate are necessary to form 1.21 moles of carbon dioxide? calcium carbonate (s)⟶ calcium oxide (s)+ carbon dioxide (g) ______________moles calcium carbonate

Answer 1

To form 1.21 moles of carbon dioxide, 1.21 moles of calcium carbonate are necessary.

Step-by-step explanation:

To determine the number of moles of calcium carbonate necessary to form 1.21 moles of carbon dioxide in the given reaction, we need to use the mole ratio of calcium carbonate to carbon dioxide.

The balanced equation shows that 1 mole of calcium carbonate reacts to form 1 mole of carbon dioxide. Therefore, the number of moles of calcium carbonate needed is also 1.21 moles.

Example:

CaCO3(s) ⟶ CaO(s) + CO2(g)

Since the reaction stoichiometry is 1:1 between calcium carbonate and carbon dioxide, the number of moles of calcium carbonate required is also 1.21 moles.