Question

Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3.

Answer 1

`\sf y - 1 = (1)/(3) (x - 6)`

Explanation:

Equation of line in point slope form: y - y₁ = m(x - x₁)

m₁ = -3

Product of slope of Perpendicular lines m* m₁= -1

`\sf m = (-1)/(m_1)\\\\m= (-1)/(-3)\\\\ \boxed{m= (1)/(3)}`

The line passes through ( 6 , 1)

Substitute the coordinates and slope in the equation,

`\sf y - 1 = (1)/(3)*(x - 6)`