Question

You measure an electric field of 1.24×10⁶ n/c at a distance of 0.165 m from a point charge. there is no other source of electric field in the region other than this point charge. What is the magnitude of the charge?

Answer 1

The magnitude of the charge creating an electric field of 1.24×10^6 N/C at a distance of 0.165 m can be calculated using the formula Q = Er^2/k, where Q is the charge, E is the electric field, r is the distance, and k is Coulomb's constant.

Step-by-step explanation:

The magnitude of an electric field created by a point charge can be determined using Coulomb's law. The formula for this is E = kQ/r^2, where E is the electric field in Newtons per Coulomb (N/C), k is Coulomb's constant (8.99×10^9 N·m^2/C^2), Q is the magnitude of the charge, and r is the distance from the charge in meters.

To solve for Q, the formula can be rearranged to: Q = E × r^2 / k. Plugging in the given values, the magnitude of the charge (Q) can be determined. Given that E = 1.24×10^6 N/C, k = 8.99×10^9 N·m^2/C^2, and r = 0.165 m, the calculation is Q = (1.24×10^6 N/C) × (0.165 m)^2 / (8.99×10^9 N·m^2/C^2).