Final answer:
To find the number of moles of nitrogen in 0.247 g of N₂O, we divide the mass by the molar mass of N₂O (44 g/mol) to get the moles of N₂O and then multiply by 2 to get the moles of nitrogen, resulting in 0.011228 moles of nitrogen.
Step-by-step explanation:
To calculate the number of moles of nitrogen (N) in 0.247 g of dinitrogen monoxide (N₂O), we first need to know the molar mass of N₂O. The molar mass can be calculated by adding the molar masses of 2 nitrogen atoms (N₂) and 1 oxygen atom (O). Since N has a molar mass of 14 g/mol and O has a molar mass of 16 g/mol, the formula N₂O would have a molar mass of (2 × 14) + 16 = 44 g/mol.
Next, we calculate the moles of N₂O in 0.247 g:
- Divide the mass of N₂O by its molar mass: 0.247 g / 44 g/mol = 0.005614 mol of N₂O.
- Since each molecule of N₂O contains two atoms of nitrogen, to find the moles of N, we multiply the moles of N₂O by 2: 0.005614 mol × 2 = 0.011228 mol of N.
Therefore, there are 0.011228 moles of nitrogen (N) in 0.247 g of N₂O.