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5 votes
Find the distance round to the nearest tenth (-8, -6) (-3,-2)​

User Ziewvater
by
4.8k points

2 Answers

9 votes

Answer:

6.4

Explanation:

d=√((−3−(−8))^2+(−2−(−6))^2)

d=√((5)^2+(4)^2)

d=√(25+16)

d=√(41)

d=6.403124

d=6.4

User Sayou
by
4.2k points
12 votes

Answer:


\displaystyle d \approx 6.4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Coordinates (x, y)

Algebra II

  • Distance Formula:
    \displaystyle d = √((x_2-x_1)^2+(y_2-y_1)^2)

Explanation:

Step 1: Define

Point (-8, -6)

Point (-3, -2)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

  1. Substitute in points [Distance Formula]:
    \displaystyle d = √((-3+8)^2+(-2+6)^2)
  2. [√Radical] (Parenthesis) Add:
    \displaystyle d = √((5)^2+(4)^2)
  3. [√Radical] Evaluate exponents:
    \displaystyle d = √(25+16)
  4. [√Radical] Add:
    \displaystyle d = √(41)
  5. [√Radical] Evaluate:
    \displaystyle d = 6.40312
  6. Round:
    \displaystyle d \approx 6.4
User Saravanan M
by
4.7k points