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How long will it take for the concentration of a to decrease from 0.500 m to 0.200 m in the first-order reaction a → b? (k = 0.800 s⁻¹)

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Final answer:

The time it takes for the concentration of A to decrease from 0.500 M to 0.200 M in the given first-order reaction is approximately 0.603 seconds.

Step-by-step explanation:

The given reaction is a first-order reaction, where the reactant A is converting to substance B. We can use the formula for the first-order reaction to calculate the time it takes for the concentration of A to decrease from 0.500 M to 0.200 M.

The formula for a first-order reaction is:

ln([A]₂/[A]₁) = -kt

Where [A]₁ is the initial concentration of A, [A]₂ is the final concentration of A, k is the rate constant, and t is the time required. Rearranging the equation, we get:

t = -(ln([A]₂/[A]₁))/k

Substituting the given values, we get:

t = -(ln(0.200/0.500))/0.800

Using a calculator, we can evaluate this expression to find the required time, which comes out to be approximately 0.603 seconds.

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