Final answer:
The compound with the given molecular formula C8H14O3 and IR absorptions at 1,810 cm⁻¹ and 1,770 cm⁻¹, and ¹H NMR peaks at 1.25 ppm (doublet, 12H) and 2.65 ppm (septet, 2H), likely has a cyclic ester (lactone) structure.
Step-by-step explanation:
The compound with the molecular formula C8H14O3 has IR absorptions at 1,810 cm⁻¹ and 1,770 cm⁻¹. The ¹H NMR spectrum shows peaks at 1.25 ppm (doublet, 12H) and 2.65 ppm (septet, 2H). Based on this information, we can determine the structure of the compound.
The IR absorptions at 1,810 cm⁻¹ and 1,770 cm⁻¹ suggest the presence of a carbonyl group. The ¹H NMR peaks at 1.25 ppm (doublet, 12H) and 2.65 ppm (septet, 2H) indicate the presence of two different types of hydrogen atoms.
One possible structure for the compound is a cyclic ester (lactone) with a molecular formula of C8H14O3. The carbonyl group could be located at one of the carbons in the ring, and the different types of hydrogen atoms could be attached to different carbons in the ring.