Final answer:
The volume of the solid formed by revolving the region bounded by x = y² and 2x = y + 1 about the y-axis, calculated using the shell method, is 49π/20.
Step-by-step explanation:
To find the volume of the solid generated by revolving the region bounded by x = y² and 2x = y + 1 around the y-axis, we first sketch the region. The intersection points of the curves can be found by setting x = y² equal to 2x = y + 1, solving for y. We find that y equals 0 and 1, which are our bounds for integration.
To use the shell method, consider a typical shell at position y with height 2x - y² and radius y. The volume of the shell with thickness delta y is approximately 2πy(2x - y²) delta y. Integrating this from y = 0 to y = 1 gives us the total volume:
V = ∫₀¹ 2πy(2y + 1 - y²) dy
After computing the integral, we find the volume to be 49π/20, which is answer choice (a).