Final answer:
The question involves using projectile motion concepts to calculate the horizontal distance, the height from which the ball was thrown, and the time taken to drop 10.0 m in a scenario where a ball is tossed from a window with an initial velocity at an angle.
Step-by-step explanation:
The student's question involves a projectile motion scenario where a ball is thrown with an initial velocity at an angle from an elevated position. Given the initial conditions and the duration until it hits the ground, we have to solve for the horizontal displacement, the height of the building, and the time taken to drop 10.0 m. Projectile motion problems typically involve splitting the motion into horizontal (x) and vertical (y) components and solving them separately using kinematic equations.
(a) To find the horizontal distance from the base of the building, we use the horizontal component of the initial velocity which does not change due to the absence of air resistance. The horizontal distance is found by multiplying the horizontal component of the velocity by the time of flight.
(b) To determine the height from which the ball was thrown, we use the vertical motion equations taking into account the acceleration due to gravity and the vertical component of the initial velocity.
(c) Calculating the time to reach a point 10.0 m below the launch level involves analyzing the vertical motion only, using the distance fallen and acceleration due to gravity.
These calculations illustrate the application of kinematic equations to determine various parameters in two-dimensional motion under gravity.