Final answer:
The unknown compound with the molecular formula C₆H₁₄O and an IR peak at 3000 cm⁻¹ is examined through IR and NMR spectroscopy to identify its structure based on absorption frequencies corresponding to various chemical bonds.
Step-by-step explanation:
The question pertains to infrared (IR) spectroscopy and nuclear magnetic resonance (NMR) spectroscopy, which are analytical techniques used to determine the structure of an unknown organic compound. Considering the molecular formula C₆H₁₄O and the strong IR absorption peak at 3000 cm⁻¹, this is indicative of the presence of C-H bonds found in alkanes.
This peak, however, isn't very distinctive as most organic molecules have such C-H bonds. When looking up IR spectra, the absorption of carbon-carbon single bonds in the fingerprint region, carbon-carbon double bonds, and carbon-carbon triple bonds are observed and compared against known compounds' spectra. The absorption frequency relates to the bond strength and is described using the analogy of springs with varying 'bounces'.
For instance, alkynes show characteristic IR absorbance in the range of 2100-2250 cm⁻¹ due to the triple bond stretching, and terminal alkenes have absorption at approximately 3300 cm⁻¹ for the sp-hybridized carbon-hydrogen bond stretching.